P(x)=-16x^2-32x

Solution for P(x)=-16x^2-32x equation:

(P)=-16P^2-32P

We move all terms to the left:

(P)-(-16P^2-32P)=0

We get rid of parentheses

16P^2+32P+P=0

We add all the numbers together, and all the variables

16P^2+33P=0

a = 16; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·16·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*16}=\frac{-66}{32}
=-2+1/16
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*16}=\frac{0}{32}
=0
$